B+2=b^2+12b+20

Solution for B+2=b^2+12b+20 equation:

+2=B^2+12B+20

We move all terms to the left:

+2-(B^2+12B+20)=0

We get rid of parentheses

-B^2-12B-20+2=0

We add all the numbers together, and all the variables

-1B^2-12B-18=0

a = -1; b = -12; c = -18;
Δ = b2-4ac
Δ = -122-4·(-1)·(-18)
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{2}}{2*-1}=\frac{12-6\sqrt{2}}{-2}
$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{2}}{2*-1}=\frac{12+6\sqrt{2}}{-2}
$